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(3(6)/2)v+10=3^2v+9
We move all terms to the left:
(3(6)/2)v+10-(3^2v+9)=0
Domain of the equation: 2)v!=0We add all the numbers together, and all the variables
v!=0/1
v!=0
v∈R
18v-(3^2v+9)+10=0
We get rid of parentheses
18v-3^2v-9+10=0
We add all the numbers together, and all the variables
18v-3^2v+1=0
We move all terms containing v to the left, all other terms to the right
18v-3^2v=-1
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